On Solvable Groups and Circulant Graphs
Author: Dobson E.
Source: European Journal of Combinatorics, Volume 21, Number 7, October 2000 , pp. 881-885(5)
Publisher: Academic Press
Abstract:
Let
be Eulers phi function. We prove that a vertex-transitive graph
of order n, with gcd(n,
(n)) = 1, is isomorphic to a circulant graph of order n if and only if Aut(
) contains a transitive solvable subgroup. As a corollary, we prove that every vertex-transitive graph
of order n is isomorphic to a circulant graph of order n if and only if for every such
,Aut(
) contains a transitive solvable subgroup and n = 4, 6, or gcd(n,
(n)) = 1. Copyright 2000 Academic Press
Language: English
Document Type: Research article
Affiliations: Department of Mathematics, Louisiana State University, Baton Rouge, LA 70808, U.S.A.
Publication date: 2000-10-01
- In this: publication
- By this: publisher
- In this Subject: Mathematics and Statistics
- By this author: Dobson E.

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