On Solvable Groups and Circulant Graphs

Author: Dobson E.

Source: European Journal of Combinatorics, Volume 21, Number 7, October 2000 , pp. 881-885(5)

Publisher: Academic Press

Buy & download fulltext article:

OR

Price: $52.63 plus tax (Refund Policy)

Abstract:

Let phiv be Euler’s phi function. We prove that a vertex-transitive graphGgr of order n, with gcd(n, phiv(n)) = 1, is isomorphic to a circulant graph of order n if and only if Aut(Ggr) contains a transitive solvable subgroup. As a corollary, we prove that every vertex-transitive graph Ggr of order n is isomorphic to a circulant graph of order n if and only if for every such Ggr,Aut(Ggr) contains a transitive solvable subgroup and n = 4, 6, or gcd(n, phiv(n)) = 1. Copyright 2000 Academic Press

Language: English

Document Type: Research article

Affiliations: Department of Mathematics, Louisiana State University, Baton Rouge, LA 70808, U.S.A.

Publication date: 2000-10-01

Related content

Tools

Key

Free Content
Free content
New Content
New content
Open Access Content
Open access content
Subscribed Content
Subscribed content
Free Trial Content
Free trial content

Text size:

A | A | A | A
Share this item with others: These icons link to social bookmarking sites where readers can share and discover new web pages. print icon Print this page